Sometimes, it is necessary to find the log(logarithm) of a number when there is no log table around.
so, the only thing you got is your mind.
below is a method which can be used to calculate the logarithm of a number if there is no log table to use.
this is also helpful if the number is too large to be calculated by a calculator. (the mind does n)
first of all, remember the following basic log values (its no harm to remember these even if you have log table).
log 2 = 0.301
log 3 = 0.477
log 5 = 0.699
log 7 = 0.845
these four values can be applied to calculate the log of any number (size does not matter).
and a formula:
log(a+b)=log a + ( b / (2.42*a) )
main method();
for example consider a small value:
log 737=?
=>log (737) = log (7.37 * 10^2)
=>log (7.37 ) + log (10^2) [ log mn = log m + log n]
=>log (7.37) +2 [ log 10^n = n]
=>log(7 + 0.37) + 2
now apply the formula:
=>log(7)+ 0.37/2.42*7 + 2
it comes out to be 2.867
which the log value for 737.
now this technique can be applied to any number.
Thank you,
hope it helps.
so, the only thing you got is your mind.
below is a method which can be used to calculate the logarithm of a number if there is no log table to use.
this is also helpful if the number is too large to be calculated by a calculator. (the mind does n)
first of all, remember the following basic log values (its no harm to remember these even if you have log table).
log 2 = 0.301
log 3 = 0.477
log 5 = 0.699
log 7 = 0.845
these four values can be applied to calculate the log of any number (size does not matter).
and a formula:
log(a+b)=log a + ( b / (2.42*a) )
main method();
for example consider a small value:
log 737=?
=>log (737) = log (7.37 * 10^2)
=>log (7.37 ) + log (10^2) [ log mn = log m + log n]
=>log (7.37) +2 [ log 10^n = n]
=>log(7 + 0.37) + 2
now apply the formula:
=>log(7)+ 0.37/2.42*7 + 2
it comes out to be 2.867
which the log value for 737.
now this technique can be applied to any number.
Thank you,
hope it helps.
awsum
ReplyDeleteNice.....
ReplyDeleteHow will log of 676 be calculated?
ReplyDeletelog (676) = log (338 * 2 * 100)
Delete=> log(338) + log2 + log(10^2)
=>log(3.38) + 0.301 + 2
=>log(3) + 0.38/(2.42*3) + 0.301 + 2
=>0.477 + 0.38/(2.42*3) + 0.301 + 2
=>2.83
hope it helps.
Thanks
Nice this really helps. Thankyou :)
ReplyDeleteAwsme!
ReplyDeleteAwesome method
ReplyDeletemarvellous
ReplyDeletethank you u made my day ..
ReplyDeletegood
ReplyDeleteNice trick bbbbbbbbbbbbbbbbbbbbbbbbro <3 :)
ReplyDeleteThe method is very nice,
ReplyDeletebut could you plz explain from where did this 2.42 came?